Get current page URL, without the parameters?

[EvanGR]

Hello,

I want to get the current page URL, excluding the parameters...
e.g. /mycategory/mysubcategory?param=1
The above, without the bold part.

Reason: I want to create custom page variation links with my own parameters.

I want to do it from the product category view file, if that makes any difference (it shouldn't).

Any ideas?

Thanks

[AH]

You can use the base joomla methods

https://api.joomla.org/cms-3/classes/Joomla.CMS.Uri.Uri.html#method_base

[PRO]

$jinput = JFactory::getApplication()->input;
$category=$jinput->getInt('virtuemart_category_id', 0);


$category_url = JRoute::_ ( 'index.php?option=com_virtuemart&view=category&virtuemart_category_id=' . $category , FALSE);

[EvanGR]

Thank you!